摘要:
下文讲述sqlserver2012中cume_dist函数的详细使用说明
实验环境:sqlserver 2012
cume_dist计算原理:
在分组中小于等于当前值的行数/当前分组的总行数
例:
declare @test table(keyId int,info varchar(20),qty int) insert into @test (keyId,info,qty)values(-1,'a',2) insert into @test (keyId,info,qty)values(1,'a',2) insert into @test (keyId,info,qty)values(2,'a',10) insert into @test (keyId,info,qty)values(3,'b',8) insert into @test (keyId,info,qty)values(4,'c',8) insert into @test (keyId,info,qty)values(5,'d',8) insert into @test (keyId,info,qty)values(6,'b',9) /* 从下文的输出我们可以看出 当前无分组 所以总行数为7 第一行keyId=-1 在整个行中的分布比它小或等于它的值没有 所以它为第一行 cume_dist = 1/7 依次类推 keyId=1 cume_dist 2/7 */ select *, cume_dist() over(order by keyId) as cume_dist from @test -------输出-------

mssql_sqlserver_cume_dist详解举例

mssql_sqlserver_cume_dist

mssql_sqlserver_cume_dist详解举例-3