Python惊人的黑客攻击

原文:https://www.geeksforgeeks.org/amazing-hacks-python/

Python 确实是最聪明、最流行的语言之一。这里有一些很酷的黑客攻击，使得 python 在所有其他语言中非常优秀。

列表理解:列表理解是摆脱编写不必要的代码行的最好和有效的技术。阅读文章了解更多。
Printing a list: List are not printed according the user requirement. They are always printed in unwanted square brackets and single quotes. But there is trivial solution to print the list efficiently by using the string’s join method. The join method turns the list into a string by casting each item into a string and connecting them with the string that join was called on.

```py

Declaring the list geek

geek = ['Geeks', 'Programming', 'Algorithm', 'Article']

Directly printing the list

print ("Simple List:", geek)

Printing the list by join method

print ('List by using join method: %s' % ', ' .join(geek))

Direct use of join method

print ('Direct apply the join method:',(", " .join(geek))) ```

```py Output: Simple List: ['Geeks', 'Programming', 'Algorithm', 'Article'] List by using join method: Geeks, Programming, Algorithm, Article Direct apply the join method: Geeks, Programming, Algorithm, Article

```

炫酷的拉链招数
转置一个矩阵:你可以读到这里关于这个。
Partition a list into N groups: We used iter() as an iterator over a sequence.

```py

Declaring the list geek

geek = ['Sun', 'Flowers', 'Peoples', 'Animals', 'Day', 'Night']

partition = list(zip (*[iter(geek)] * 2)) print (partition) ```

```py Output: [('Sun', 'Flowers'), ('Peoples', 'Animals'), ('Day', 'Night')]

```

解释 : [iter(geek)] * 2 产生一个包含 geek[]列表 2 项的列表，即长度为 2 的列表。*arg 将序列解包为函数调用的参数。因此，我们将同一个迭代器传递给 zip()两次。
同时打印多个列表的项目

```py list1 = [1, 3, 5, 7] list2 = [2, 4, 6, 8]

Here zip() function takes two equal length list and merges them

together in pairs

for a, b in zip(list1,list2): print (a, b) ```

```py Output: 1 2 3 4 5 6 7 8

```
以字符串为输入，转换为列表:

```py

Reads a string from input and type case them to int

after splitting to white-spaces

formatted_list = list(map(int, input().split())) print(formatted_list) ```

```py Input: 2 4 5 6 Output: [2, 4, 5, 6]

```
将列表列表转换为单个列表

```py

import the itertools

import itertools

Declaring the list geek

geek = [[1, 2], [3, 4], [5, 6]]

chain.from_iterable() function returns the

elements of nested list

and iterate from first list

of iterable till the last

end of the list

lst = list(itertools.chain.from_iterable(geek)) print(lst) ```

```py Output: [1, 2, 3, 4, 5, 6]

```
打印重复字符:任务是打印这样的图案 Geeeeekkkkss。因此，我们可以轻松打印此图案，而无需使用 for loop。

```py

+ used for string concatenation

To repeat the character n times, just multiply n

with that character

print ("G" + "e"5 + "k"4 + "s"*2) ```

```py Output: Geeeeekkkkss

```

阅读更多: 关于Python的 10 个有趣事实 T5【参考:https://www.quora.com/What-are-some-cool-Python-tricks

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